1 $101_2 + 1101_2 =$ flag bookmark A $10111_2$ B $10110_2$ C $10010_2$ D $1010_2$ T4 Chapter 2.1d Addition and Subtraction of Numbers in Various Bases $101_2 = 5$ and $1101_2 = 13$. 5 + 13 = 18 = 16 + 2 = $10010_2$.
2 The mass of a hydrogen atom is $1.7 \times 10^{-24}$ g and the mass of an oxygen atom is $2.7 \times 10^{-23}$ g. One molecule of water is made up of two hydrogen atoms and one oxygen atom. Find the mass, in g, of one molecule of water. flag bookmark A $5.74 \times 10^{-23}$ B $5.57 \times 10^{-23}$ C $3.04 \times 10^{-23}$ D $2.87 \times 10^{-23}$ Mass = $2(1.7 \times 10^{-24}) + 2.7 \times 10^{-23} = 0.34 \times 10^{-23} + 2.7 \times 10^{-23} = 3.04 \times 10^{-23}$ g.
3 Diagram 1 shows the distance-time graph of a runner. Given the speed of the runner is 5 m s⁻¹, what is the value of x? flag bookmark A 100 B 110 C 125 D 140 T4 Chapter 7.1c Solving Problems Involving Distance-Time Graphs The gradient of the graph is the speed: $\frac{x - 15}{25} = 5$, so $x - 15 = 125$ and $x = 140$.
4 Diagram 2 shows the location of Aniq's house from his school. Using the scales of 2 cm : 2 units for both axes, calculate the gradient from Aniq's house to his school. flag bookmark A $-2$ B $-\frac{1}{2}$ C $\frac{1}{2}$ D 2 The same scale is used on both axes. From the house to the school the line goes down, and the vertical drop is half of the horizontal distance (for example, down 2 units for every 4 units to the right). So the gradient = $\frac{-2}{4} = -\frac{1}{2}$.
5 The ratio of the price of a baju kurung to the price of a cheongsam is 7 : 4. Calculate the price of a cheongsam, if the price of a baju kurung is RM 84. flag bookmark A RM 8 B RM 16 C RM 30 D RM 48 7 parts = RM84, so 1 part = RM12. Cheongsam = 4 × 12 = RM48.
6 Which of the following statements is true for a rhombus? flag bookmark A Has one axis of symmetry. B The opposite sides are parallel. C Opposite angles are different in size. D Only has two sides of the same length. A rhombus has four equal sides, both pairs of opposite sides are parallel and opposite angles are equal. It has two axes of symmetry (its diagonals). So only B is true.
7 Diagram 3 shows the plan of a combined solid. Which of the following has the plan as above? flag bookmark A B C D The plan is a square with a dashed circle inside it. The circle must be hidden below the square, so the solid is a cuboid sitting on top of a cylinder whose diameter equals the side of the cuboid. This is B.
8 Diagram 4 shows a circle with centre O. OPR is an isosceles triangle. Calculate the value of x. flag bookmark A 15° B 25° C 35° D 75° OP = OR, so ∠ORP = ∠OPR = 35°. Then ∠PRQ = 35° + 40° = 75°, so the angle at the centre ∠POQ = 2 × 75° = 150°. OP = OQ, so $x = \frac{180° - 150°}{2} = 15°$.
9 Diagram 5 shows two circles with centres O and W respectively. PQRS is a common tangent to both circles at Q and R. RTU is a tangent to the circle. Calculate the value of x + y. flag bookmark A 170° B 175° C 190° D 195° RQ and RT are tangents from R to circle O, so in quadrilateral OQRT, y = 180° − 55° = 125°. VQW is a straight line, so ∠WQR = ∠PQV = 25° (vertically opposite). WR ⊥ QR, so x = 90° − 25° = 65°. x + y = 190°.
10 Diagram 6 shows five pentagons, P, I, II, III and IV, drawn on a Cartesian plane. Which of the pentagons I, II, III and IV, are congruent to P? flag bookmark A I and II B I and IV C II and III D II and IV T5 Chapter 5.1a Congruency and the Properties of Triangle Congruency Congruent shapes have exactly the same side lengths and angles; they may be turned or flipped. Comparing the grid lengths, pentagons II and III have the same shape and size as P, while I and IV are different.